character input in an array in java.....how?????

Code:

char[] yourArray = new char[3];
yourArray[0] = 'a';
yourArray[1] = 'b';
yourArray[2] = 'c';


BIT0103-Ovid wrote:this topic has been moved to the java help section

Code:


package myPackage;

import java.util.Scanner;

public class ForHabib {

   public static void main(String[] args) {
      //use Scanner to take input
      Scanner myScanner = new Scanner(System.in);
      //that's your character array
      char[] myArray = new char[3];

      for (int i = 0; i < myArray.length; i++) {
         //as we don't have any nextChar() method, we are going to take input and keep it in a string
         String temp = myScanner.next();
         //and then we are going to put the first character of that string to your array
         myArray[i] = temp.charAt(0);
      }

      for (int i = 0; i < myArray.length; i++) {
         System.out.println(myArray[i]);
      }
   }
}


Code:


ami
bas
qwe


Code:


a
b
q


Code:



import java.io.IOException;

public class ArrayInJava {

    public static void main(String[] args) throws IOException {
        char[] myArray = new char[3];

        System.out
                .println("Eneter your characters and press enter after every characters");
        for (int i = 0; i < myArray.length; i++) {
            myArray[i] = getChar();
        }

        System.out.println("your chacters are: ");
        for (int i = 0; i < myArray.length; i++) {
            System.out.print(myArray[i] + ",");
        }
    }

    public static char getChar() throws IOException {
        char ch = (char) System.in.read();
        byPassReturnKey();
        return ch;
    }

    public static void byPassReturnKey() throws IOException {
        while ((char) System.in.read() != '\n')
            ;
    }

}


bit0112-rokon wrote:hmm.. its quite easy. I think you guys are familiar with Scanner class. But there is no method in Scanner class to take char input. So you are facing difficulties, right?

okay here I will show you two way, how to take char as a input in Java.
you may feel it is difficult first time, but it will work nicely. Okay. so first now get first One _

you guys are also familiar about System.out.println(), right? but do you know there is something like System.in.read()?
when you'll learn Java I/O, you will be clear about it. dont worry here, I'll try to give you some idea.

System.in.read() takes input from keyboard. But it has a problem. if you press Return Key (enter), it will take return key as a input. So there should a way to bypass the return key. Okay?

Now better look through the code _

Code:



import java.io.IOException;

public class ArrayInJava {

    public static void main(String[] args) throws IOException {
        char[] myArray = new char[3];

        System.out
                .println("Eneter your characters and press enter after every characters");
        for (int i = 0; i < myArray.length; i++) {
            myArray[i] = getChar();
        }

        System.out.println("your chacters are: ");
        for (int i = 0; i < myArray.length; i++) {
            System.out.print(myArray[i] + ",");
        }
    }

    public static char getChar() throws IOException {
        char ch = (char) System.in.read();
        byPassReturnKey();
        return ch;
    }

    public static void byPassReturnKey() throws IOException {
        while ((char) System.in.read() != '\n')
            ;
    }

}


I think there is some unknown part for you. like throws IOException.
Okay dont worry. Just use it. We will discuss about it later.

btw if any problem let me know..

and I'll post the second way of taking char input later if you dont understand it.

cheers!!

BIT0122-Amit wrote:
Sigh...

try to give a solution that will help them use what they already know, not something that will make them use something they have absolutely no idea about.

bit0112-rokon wrote:

Idea nai, ar mane ai na j, idea hobe na.. taina? and secondly ami bolci.. aita na bujle ami second way ta debo..... and ami firstly 2ta way chinta korci.. tar modde aita best mone hoice.
akhon obosso amr mathai aro onekgula way asce ...

btw tor way ta good.. but not better ...
amr mone hoi nijera torko kore aikhane oder k confused korer kono mane nai.. better j help chaice .. se kototuku bujlo seta beshi important ....

BIT0122-Amit wrote:here you go:

Code:


package myPackage;

import java.util.Scanner;

public class ForHabib {

   public static void main(String[] args) {
      //use Scanner to take input
      Scanner myScanner = new Scanner(System.in);
      //that's your character array
      char[] myArray = new char[3];

      for (int i = 0; i < myArray.length; i++) {
         //as we don't have any nextChar() method, we are going to take input and keep it in a string
         String temp = myScanner.next();
         //and then we are going to put the first character of that string to your array
         myArray[i] = temp.charAt(0);
      }

      for (int i = 0; i < myArray.length; i++) {
         System.out.println(myArray[i]);
      }
   }
}


read the comments for explanation.

Sample Input:

Code:


ami
bas
qwe


sample output

Code:


a
b
q


there is also several other methods for doing the same task in more efficient way(for example, bufferreader, or the System.in.read() method) But as you are only a beginner and possibly only know about Scanner till now, use this.

And you better use the code tag next time when you are posting a code.

AND
DO NOT USE ... IN TOPIC TITLE.
why?
1. It looks ugly.
2. It looks horrible.
3. It is what you use in chatting. Are you chatting?

bit0112-rokon wrote:
apni Java naming convention maintain koren nai.. bishal oporadh ... ar jonno obossoi apnake shasti pete hobe.....
package name always small letter hoi.. not myPakage, it shoud be mypakage or my.pakage or amit.pakage or amit.bla.bla.bla



note: shasti map kore deya jai.. if amke coffee kkhayer taka dis......

BIT0102-Mohaimin wrote:Often I feel bored to see irrelevant posts in our forum... I came here to help... But unfortunately... I have failed to identify that the problem was solved or not... The solutions are lost inside a dark deep forest of stupid posts...

Code:


public static void main(String[] args) {
      char[] arr = new char[10];
      
      for (int i = 0; i < arr.length; i++) {
         try {
            arr[i] = (char)System.in.read();
                                // It reads the unicode value (Java... so, NOT ASCII value), you need to convert to char
         } catch (IOException e) {
            e.printStackTrace();
         }
      }
   }